Solve for x . Round to the nearest tenth.

Question

Solve for x  . Round to the nearest tenth.

BlackTom AI · Accepted Answer

The problem statement provided is incomplete. It says: 'Solve for x. Round to the nearest tenth.' but does not include the equation or any context to solve for x. Without the actual equation, the value of x cannot be determined.

What you should provide or look for next:
- The full equation or expression involving x. For example, it could be linear (ax + b = c), quadratic (ax^2 + bx + c = 0), or something more complex (involving fractions, exponents, or radicals).

If the equation were linear (for instance, 3x + 7 = 22):
- Subtract 7 from both sides: 3x = 15
- Divide both sides by 3: x = 5.0
- Round to the nearest tenth: 5.0

If the equation were quadratic (for instance, 2x^2 - 4x - 6 = 0):
- Use the quadratic formula x = [4 ± sqrt(16 + 48)] / 4 = [4 ± sqrt(64)] / 4 = [4 ± 8] / 4, yielding x = 3.0 or x = -1.0
- Round results to the nearest tenth as needed: 3.0 and -1.0

If the equation involved a more complex setup (radicals, fractions, or multiple steps), you would:
- isolate the term containing x,
- perform inverse operations to solve for x,
- check for extraneous solutions (especially with radicals or squaring both sides), and
- round the final numeric value to the nearest tenth.

Please provide the exact equation (or link to it) so I can walk through the specific steps and produce the rounded solution to the nearest tenth.

PRECALC141-033 2.6 Practice Problems

Solve for x . Round to the nearest tenth.

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