你还在为考试焦头烂额?找我们就对了!
我们知道现在是考试月,你正在为了考试复习到焦头烂额。为了让更多留学生在备考与学习季更轻松,我们决定将Gold会员限时免费开放至2025年12月31日!原价£29.99每月,如今登录即享!无门槛领取。
助你高效冲刺备考!
题目
PHYSICS 1201 SU2025 (10585) MT2 Exam- Requires Respondus LockDown Browser
单项选择题
A flat coil having 40 turns, each one of cross-sectional area 12.0 cm2, is oriented with its plane perpendicular to a uniform magnetic field. The field varies steadily from 0.00 T to 1.20 T in 20.0 ms. What emf is induced in the coil during this time?
选项
A.0.288 V
B.4.88 V
C.0 V
D.8.02 V
E.2.88 V
查看解析
标准答案
Please login to view
思路分析
To determine the induced emf in a coil, we use Faraday’s law for a multi-turn coil: |ε| = N A (dB/dt), where N is the number of turns, A is the cross-sectional area of the coil, and dB/dt is the rate of change of the magnetic field.
First, convert the given area to square meters: A = 12.0 cm^2 = 12.0 × 10^-4 m^2 = 1.20 × 10^-3 m^2.
Next, find dB/dt from the field change: B goes from 0.00 T to 1.20 T in Δt = 20.0 ms = 0.02......Login to view full explanation登录即可查看完整答案
我们收录了全球超50000道考试原题与详细解析,现在登录,立即获得答案。
类似问题
A bar magnet is passed through a coil of wire. The induced current is greatest when
Lenz's law is a rule regrading
A plane conducting geometry is placed in a spatially uniform magnetic field such that there is a non-zero magnetic flux through the geometry. From the following statements select all that are true.
A uniform cross-section conductor has a resistance of 2 Ω. The conductor is used to make a rectangular 24 cm x 20 cm loop. The loop is rotated in a uniform magnetic field of 12 T with a rotational speed of 3,064 rpm. The axis of rotation passes through the mid-points of two opposite sides of the ractangular loop, and is perpendicular to the magnetic field. At time instant t = 0 ms, the plane of the loop is perpendicular to the magnetic field. Assume that there are no losses. Therefore, at any time instant, all the mechanical power delivered to the loop is converted into electrical power which is all converted into thermal power. The rotating loop is cooled at a rate that keeps the loop temperature at a constant value. What is the magnitude of the torque needed to rotate the loop at t = 5 ms? Calculate the answer in the units of newton-meter (N.m). Write your answer in decimal form with two digits to the right of the decimal point (e.g. 5.37); do not write any units or sign. Please note: rpm = revolutions per minute ms = milli-second
更多留学生实用工具
希望你的学习变得更简单
为了让更多留学生在备考与学习季更轻松,我们决定将Gold 会员限时免费开放至2025年12月31日!