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MGS*3100*01.2025FA Test 03: Chap 10,11

Single choice

Scenario 9.9 "Gollee those cats sure go through a lot of food," Geoff exclaimed as he saw the shopping list pad that had been pre-printed with the words "cat food" at the top. He pondered a different approach to shopping for the furry little darlings, reviewed his shopping records, and discovered the following. The price of cat food has held steady at 89 cents per can. Despite feigning indifference, each of the seven cats nibbles their way through an average of one can per day, three hundred sixty five days a year. The price of gasoline has held constant at $3.50 per gallon and his pickup uses a gallon each way to the cat food store. The cost to hold a can of cat food is 10% of the unit price. Use the information in Scenario 9.9 to determine the amount of time in-between trips to the cat food store if Geoff wisely elects to follow an EOQ policy for obtaining cat food.

Options
A.about six months
B.about three months
C.about three weeks
D.about three days
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Step-by-Step Analysis
We’re given Scenario 9.9 data and asked to determine the time between EOQ-replenishment trips for cat food. First, restating the key figures: there are 7 cats, each eats about 1 can per day, so annual demand D = 7 × 1 × 365 = 2,555 cans/year. The price per can is $0.89, and the holding cost is 10% of unit price, so h = 0.10 × $0.89 = $0.089 per can per year. The travel cost per replenishment order comes from gasoline use: the pickup uses 1 gallon each way, so a round trip consumes 2 gallons. At $3......Login to view full explanation

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