Calculate the following dilutions:

A. A 1:2 grape juice solution in a total volume of 5 ml.

B. A 1:5 dilution of grape juice in a total volume of 5 ml.

Dilutions Amount of Water (ml) Amount of Juice (ml)
1:2
1:5

Question

Calculate the following dilutions:

A. A 1:2 grape juice solution in a total volume of 5 ml.

B. A 1:5 dilution of grape juice in a total volume of 5 ml.

Dilutions	Amount of Water (ml)	Amount of Juice (ml)
         1:2		
        1:5

BlackTom AI · Accepted Answer

Restating the problem in my own words: you are asked to calculate two dilutions in a total volume of 5 ml each. A is a 1:2 dilution of grape juice, and B is a 1:5 dilution, with a provided table showing amounts of water and juice. The answer options give specific amounts of water and juice for A and B, and you must evaluate each option.

First, let's consider how to interpret a 1:2 or 1:5 dilution. A common convention for dilutions is to interpret a ratio as juice (solvent or solute of interest) to water (diluent) in that order. If so, a 1:2 dilution means 1 part juice to 2 parts water, for a total of 3 parts. When the total volume is fixed at 5 ml, the proportions would be:
- For 1:2 (juice:water = 1:2): juice = 5 × (1/3) ≈ 1.67 ml; water ≈ 3.33 ml.
- For 1:5 (juice:water = 1:5): juice = 5 × (1/6) ≈ 0.83 ml; water ≈ 4.17 ml.
These are the values you would expect if the standard interpretation holds. Note that sometimes people label dilutions differently (e.g., water:juice), or may use 1:X to mean something else, so ambiguity can arise and you should check the convention given in the material. With the numbers above in mind, we can evaluate each option.

Option 1: A. 2.5 ml water & 2.5 ml juice, B. 4 ml water & 1 ml juice
- For A (2.5 water, 2.5 juice): this is a 1:1 ratio of juice:water, not 1:2. It does not match the requested 1:2 dilution under the common interpretation, which would require juice ≈ 1.67 ml and water ≈ 3.33 ml. Therefore A’s values are inconsistent with a 1:2 dilution.
- For B (4 ml water, 1 ml juice): this is a 1:4 juice:water ratio, not 1:5. The expected 1:5 would be juice ≈ 0.83 ml and water ≈ 4.17 ml, so this option for B also deviates from the 1:5 target.
- Overall, option 1 does not align with the standard 1:2 and 1:5 dilutions in a 5 ml total.

Option 2: A. 2 ml water & 3 ml juice, B. 2.5 ml water & 2.5 ml juice
- For A: water 2 ml and juice 3 ml yields a juice:water ratio of 3:2, which is 1.5:1, not 1:2. This does not satisfy a 1:2 dilution.
- For B: 2.5 ml water & 2.5 ml juice is again a 1:1 ratio, not 1:5. This also fails to meet the requested B dilution.
- Hence option 2 mismatches both targets.

Option 3: A. 1 ml water & 4 ml juice, B. 4.5 ml juice & 0.5 ml water
- For A: 1 ml water and 4 ml juice gives juice:water = 4:1, a very concentrated ratio (4:1) far from 1:2. It does not satisfy the 1:2 target.
- For B: 4.5 ml juice and 0.5 ml water yields water:juice = 0.5:4.5 = 1:9, or juice:water = 9:1, which is far from 1:5. This also deviates from the stated dilution.
- Overall, option 3 is inconsistent with both specified dilutions.

Option 4: A. 1.5 ml water & 3.5 ml juice, B. 3 ml water & 2 ml juice
- For A: 3.5 ml juice and 1.5 ml water gives juice:water = 3.5:1.5 ≈ 7:3 ≈ 2.33:1, not 1:2. This does not meet the 1:2 requirement.
- For B: 3 ml water and 2 ml juice yields juice:water = 2:3 ≈ 0.67:1, which is not 1:5. It also fails to meet the dilution target for B.
- Thus option 4 also does not correspond to the requested dilutions.

Synthesis across options: Each option attempts to allocate 5 ml into water and juice for A and B, but none of the options provide amounts that match the conventional 1:2 (juice:water) and 1:5 (juice:water) ratios in a total volume of 5 ml. If your course or lab material uses a different convention (for example, specifying water:juice rather than juice:water, or using a fixed total volume with a different interpretation of the ratio), you would need to apply that convention to compute the exact amounts. In this exercise, the given options do not align with the standard interpretation described above, so evaluating them against that standard leads to the conclusion that none are consistent with both target dilutions.

BIOL-10-20048-S25 Lab Exam 1 - Wednesday 3/19

Calculate the following dilutions: A. A 1:2 grape juice solution in a total volume of 5 ml. B. A 1:5 dilution of grape juice in a total volume of 5 ml. Dilutions Amount of Water (ml) Amount of Juice (ml) 1:2 1:5

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