Questions
Questions

MAT137Y1 LEC 20249: Calculus with Proofs (all lecture sections) Pre-Class Quiz 42(8.3 and 8.4)

Single choice

Compute ๐‘‘ ๐‘‘ ๐‘ฅ ( โˆซ 5 ๐‘ฅ ๐‘ฅ 2 cos โก ( ๐‘ก 2 ) ๐‘‘ ๐‘ก ) . ย 

Options
A.cos โก ( ๐‘ฅ 4 ) โˆ’ cos โก ( 25 ๐‘ฅ 2 )
B.โˆ’ 2 ๐‘ฅ sin โก ( ๐‘ฅ 4 ) + 5 sin โก ( 25 ๐‘ฅ 2 )
C.โˆ’ 2 ๐‘ฅ sin โก ( ๐‘ฅ 2 ) + 2 ๐‘ฅ sin โก ( 5 ๐‘ฅ )
D.10 ๐‘ฅ cos โก ( ๐‘ฅ 4 )
E.2 ๐‘ฅ cos โก ( ๐‘ฅ 4 ) โˆ’ 5 cos โก ( 25 ๐‘ฅ 2 )
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Step-by-Step Analysis
We start by restating what is being asked and listing the answer choices so we can compare them carefully. Question and options: - Compute d/dx of the given integral expression. - Answer options: 1) cos(x^4) โˆ’ cos(25 x^2) 2) โˆ’2 x sin(x^4) + 5 sin(25 x^2) 3) โˆ’2 x sin(x^2) + 2 x sin(5 x) 4) 10 x cos(x^4) 5) 2 x cos(x^4) โˆ’ 5 cos(25 x^2) Next, Iโ€™ll analyze each option in light of how derivatives of integrals with variable limits or integrands depending on x behave. A common tool here is the Leibniz rule: when you differentiate an integral whose upper limit is a function of x, you evaluate the integrand at the upper limit times the derivative of that limit; if the integrand itself depends on x, you may also have a term from the partial derivative of the integrand with respect to x. Option 1: cos(x^4) โˆ’ cos(25 x^2) - This form resembles a difference of cosine terms evaluated at functions of x. If the origin were a simple composition derivative of cos(u) with u = x^4 or u = 25x^2, you would expect a factor from chain rule, which would yield terms like โˆ’sin(x^4)ยท4x^3 or โˆ’sin(25x^2)ยท50x. Instead, this option shows cos terms, not sin, and lacks any chain-rule-derived x-factors. Moreover, if the derivative came from evaluati......Login to view full explanation

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