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DFS_Graph_4 Context: This question pertains to the use of the Graph Abstract Data Type (ADT) implemented with an Adjacency Map, as studied in our course. Instructions: Begin the traversal at Vertex 'A'. When selecting the next vertex to visit, adhere to alphabetical order. Question: Complete the depth-first search (DFS) for the graph shown below. Guidelines: Initiate the traversal at Vertex 'A', and proceed with the exploration, selecting vertices in alphabetical order where multiple paths are available. def DFS(g, u, discovered): for e in g.incident_edges(u): v = e.opposite(u) if v not in discovered: discovered[v] = e # mark v as discovered via edge e DFS(g, v, discovered)
Options
A.A, B, E, F, G, C, D
B.A, E, F, B, C ,D, G
C.A, B, C, D, E, F, G
D.A, D, B, C, E ,F, G
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Step-by-Step Analysis
The question asks us to perform a depth-first search (DFS) on a graph starting at vertex A, choosing the next vertex to visit in alphabetical order whenever multiple options are available. The provided correct answer list is A, B, E, F, G, C, D, so the explanation will verify this ordering and explain why the other options do not conform to DFS with the given rule set.
Option 1: A, B, E, F, G, C, D
- This sequence begins at A and then proceeds to B, which is consistent with choosing the alphabetically smallest unvisited neighbor of A if B is indeed the first neighbor encountered in alphabetical order.
- From B, the DFS would look for the smallest unvisited neighbor. The sequence then goes to E, suggesting that E is the smallest unvisited neighbor of B. This aligns with the rule of exploring the smallest alphabetically available edge next.
- From E, the traversal goes to F. This implies F is the smallest unvisited neighbor of E, which can be c......Login to view full explanationLog in for full answers
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Similar Questions
The diagram below represents a problem using a search tree. Which of the following options shows the correct order of node visits to reach Wendy using Depth-First Search (DFS)?
How does depth-first search complete its search of the search tree?
DFS_Pse_2 This question pertains to the use of the Graph Abstract Data Type (ADT) implemented using an adjacency map, as studied in our course. The algorithms DFS and BFS are used to explore graphs but follow different strategies for traversal. Below is a simplified pseudocode version of a Depth-First Search (DFS) algorithm that uses recursion and a discovereddictionary to track visited vertices: DFS(Graph G, Vertex u, Map discovered): for each edge e incident to u in G: let v be the vertex opposite u on edge e if v is not in discovered: discovered[v] ← e // edge e discovered v DFS(G, v, discovered) In the DFS pseudocode, what does the discovered[v] ← e assignment represent? Graph ADT For reference: class Vertex: def __init__(self, x): self._element = x class Edge: def __init__(self, u, v, x): self._origin = u self._destination = v self._element = x def opposite(self, v): return self._destination if v == self._origin else self._origin class Graph: def __init__(self, directed=False): self._outgoing = {} self._incoming = {} if directed else self._outgoing def incident_edges(self, v): return self._outgoing[v].values()
DFS_Graph_3 Context: This question pertains to the use of the Graph Abstract Data Type (ADT) implemented with an Adjacency Map, as studied in our course. Instructions: Begin the traversal at Vertex 'd'. When selecting the next vertex to visit, adhere to alphabetical order. Question: Complete the depth-first search (DFS) for the graph shown below. Guidelines: Initiate the traversal at Vertex 'd', and proceed with the exploration, selecting vertices in alphabetical order where multiple paths are available. def DFS(g, u, discovered): for e in g.incident_edges(u): v = e.opposite(u) if v not in discovered: discovered[v] = e # mark v as discovered via edge e DFS(g, v, discovered)
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