A piece of plastic weighs 0.552 lb and occupies a volume of 166 cm3.

(1 kg = 2.205 lb; 1000 g = 1 kg)

1. The density of this plastic is [Fill in the blank],
g/cm3. (Round off your answer correctly to 2 decimal figures or 2 prds e.g. 7.08 and do NOT enter the unit in the answer. Take note, the required unit for the answer is g/cm3 ) (NO partial credit)

2. Based on the list of polymers below, the plastic is most likely made of [Fill in the blank],
. (Enter the polymer abbreviation, NO partial credit)

Question

A piece of plastic weighs 0.552 lb and occupies a volume of 166 cm3.

(1 kg = 2.205 lb; 1000 g = 1 kg)

1.  The density of this plastic is [Fill in the blank],
 g/cm3.  (Round off your answer correctly to 2 decimal figures or 2 prds e.g. 7.08 and do NOT enter the unit in the answer. Take note, the required unit for the answer is g/cm3 ) (NO partial credit)

2. Based on the list of polymers below, the plastic is most likely made of [Fill in the blank],
. (Enter the polymer abbreviation, NO partial credit)

BlackTom AI · Accepted Answer

The problem presents two blanks: first, a numeric density value to be calculated and entered with two decimal places, and second, a polymer abbreviation based on a provided list that is not present in the prompt.

First, handle the density calculation:
- Mass conversion: The piece of plastic weighs 0.552 lb. Using the given conversion 1 kg = 2.205 lb, we convert pounds to kilograms: 0.552 lb ÷ 2.205 lb/kg ≈ 0.250 kg.
- Convert to grams: 0.250 kg × 1000 g/kg ≈ 250 g.
- Volume is 166 cm3, so density = mass/volume ≈ 250 g / 166 cm3 ≈ 1.506 g/cm3.
- Rounding to two decimals yields 1.51 g/cm3. This matches the provided first answer, confirming the calculation is consistent with the instructions.

Second, determine the polymer abbreviation:
- To identify the polymer, one would normally compare the calculated density to typical densities of common polymers and consult the list of abbreviations provided in the course materials or lab handout.
- However, the prompt as given does not include the list of polymers or their abbreviations. Without that list, it is impossible to assign a specific polymer abbreviation to the plastic based solely on the density value.
- If you had the list, you would locate which polymer in that list has a density around 1.51 g/cm3 (likely within rounding tolerance) and then provide its abbreviation (e.g., PET, PEN, PMMA, etc., depending on the actual options). Since the list is missing here, the second blank cannot be definitively filled.

Summary of key points:
- Density calculation: 0.552 lb → 250 g; volume 166 cm3; density ≈ 1.51 g/cm3 after rounding.
- Polymer abbreviation: cannot be determined from the provided information because the list of polymers and their abbreviations is not included in the prompt.

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