In Chapter 8 we will discuss integration, which as we will see has a close relationship with differentiation.

Tasks:
Go to the beginning of Section 8.1 and read Definition 8.1.
Definition 8.1 (The Definite Integral) The integral of on is the signed area between the -axis and the graph of , and is denoted by .
"Signed area" means that areas above the -axis have a positive value, while areas below the -axis have a negative value.
This video contains an introduction to this concept:

Question:

Which definite integral is represented by the shaded region below?

Question

In Chapter 8 we will discuss integration, which as we will see has a close relationship with differentiation.

Tasks:
Go to the beginning of Section 8.1 and read Definition 8.1.
Definition 8.1 (The Definite Integral) The integral of  on  is the signed area between the -axis and the graph of , and is denoted by .
"Signed area" means that areas above the -axis have a positive value, while areas below the -axis have a negative value.
This video contains an introduction to this concept:

Question:

Which definite integral is represented by the shaded region below?

BlackTom AI · Accepted Answer

The question describes a definite integral and asks which integral corresponds to the shaded region. However, the provided data for answer options is missing, so I will reason about the given answer and the typical interpretation.

First, recall the definition given: the definite integral represents the signed area between the x-axis and the graph of the function over the specified interval. Areas above the x-axis contribute positively, while areas below contribute negatively.

Next, examine the supplied answer string: ∫ from 0 to 3 of 2 dx = 6. This corresponds to integrating the constant function f(x) = 2 over the interval [0, 3]. Graphically, the region under the line y = 2 above the x-axis from x = 0 to x = 3 forms a rectangle of width 3 and height 2.

To evaluate this integral, treat it as the area of that rectangle: base length = 3, height = 2. The area is base × height = 3 × 2 = 6. Since the function is positive on the interval (y = 2 > 0), the integral equals +6, consistent with the provided result.

Now, about the missing answer options: without a list of choices, we cannot compare which of them matches the shaded region. If there were other options, we would assess each one by considering the interval bounds, the integrand, and whether the area is counted positively or negatively based on the function's sign over the interval. Common pitfalls include:
- Misreading the bounds or reversing them, which would change the sign of the integral.
- Integrating the wrong function (e.g., integrating 3 instead of 2, or using a different interval).
- Assuming a negative area when the graph lies entirely above the x-axis.

In this specific case, assuming the shaded region is the area under a constant function y = 2 from x = 0 to x = 3, the integral ∫ from 0 to 3 of 2 dx correctly yields 6, matching the stated result. If the region were different (for example, under a different function or over a different interval), the value and even the sign could change accordingly.

If you can provide the actual list of answer options, I can explicitly evaluate each option and explain why it is correct or incorrect in comparison to the shaded region.

MAT133 F24-W25 W25 Week 7 Preclass Guided Reading

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