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MTH1030 -1035 - S1 2025 MTH1030/5 MTH1030/5 Week 1 lesson quiz: Vectors, lines and planes

Single choice

Here are a couple of true statements. Make sure that you understand why all these statements are true. Once you do click "I get it :)". Cross your heart and ... :) The best way to make sense of these statements is to translate them into geometry. Okay, so let [math: u]{\bf u} and [math: v] {\bf v} be vectors in R3. The cross product only makes sense for vectors in R3.[math: u×v+v×u=0] {\bf u} \times {\bf v} +{\bf v} \times {\bf u} = {\bf 0}[math: (3u)×v=3(u×v)] (3 {\bf u}) \times {\bf v}= 3({\bf u} \times {\bf v} )If [math: u] {\bf u} is a multiple of [math: v] {\bf v} , then [math: u×v=0]{\bf u} \times {\bf v} = {\bf 0}[math: u×u=0] {\bf u} \times {\bf u} = {\bf 0}

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Step-by-Step Analysis
The task presents a collection of statements about vectors in R3 and the cross product, and asks us to determine understanding. First, assess the mathematical content of the statements themselves. The cross product is anti-commutative, meaning u × v = - (v × u); therefore u × v + v × u = 0 is a correct reflection of that property. Next, scalar multiplication behaves with the cross product: (3u) × v = 3 (u × v). This follows from the bilinear property of the cross product, where scaling one......Login to view full explanation

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