Which statement is correct about the following Python code:

score = 85
if score = 90:
print("Grade A")
elif score = 80:
print("Grade B")
else:
print("Grade C")

Question

Which statement is correct about the following Python code:

score = 85
if score >= 90:
  print("Grade A")
elif score >= 80:
  print("Grade B")
else:
  print("Grade C")

BlackTom AI · Accepted Answer

The question presents a snippet that uses a conditional chain to decide which grade to print. 
Option 1: 'score is a string variable.' This is false because the code shows score = 85, which is an integer, not a string. If score were a string like '85', the comparisons could fail or behave differently depending on the string content; with the given code, the type is int, so this option misstates the actual type used.
Option 2: 'It is a loop structure which runs certain instructions repeatedly.' This is incorrect because the construct used here is an if/elif/else chain, not a loop. There is no iteration or repeated execution in this code; it evaluates the condition once and prints accordingly.
Option 3: 'elif is another way of writing else if.' This is true in Python. The elif keyword introduces an additional conditional branch following the initial if, functioning equivalently to 'else if' found in other languages, allowing multiple mutually exclusive branches to be checked in sequence.
Option 4: 'The output result is "Grade A".' This cannot be correct given score = 85. The first condition checks score >= 90 (false), the next checks score >= 80 (true), so the code prints 'Grade B', not 'Grade A'. Therefore this statement is incorrect.

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Which statement is correct about the following Python code: score = 85 if score >= 90: print("Grade A") elif score >= 80: print("Grade B") else: print("Grade C")

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