What will be the output of the following code?int a = 10;int b = 20;if (a b || b a) { System.out.println("Either a b or b a");} else { System.out.println("a is equal to b");}

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What will be the output of the following code?int a = 10;int b = 20;if (a > b || b > a) {  System.out.println("Either a > b or b > a");} else {  System.out.println("a is equal to b");}

BlackTom AI · Accepted Answer

To begin, observe the given Java code: two integers a = 10 and b = 20 are initialized. The conditional uses a logical OR: if (a > b || b > a).
Option 1: No compilation error. This is incorrect because the syntax and operators are valid in Java; the code will compile, so this cannot be the right choice.
Option 2: a is equal to b. This is false since 10 is not equal to 20, and the condition does not check for equality directly. Therefore, this branch won’t execute.
Option 3: No output. Since the condition evaluates to true (see next), the program will print something, so this option is incorrect.
Option 4: None of above. Given that one of the statements below is actually correct, this option is not accurate.
Option 5: Either a > b or b > a. Evaluate the condition: a > b is 10 > 20, which is false. b > a is 20 > 10, which is true. The logical OR of false and true is true, so the then-branch executes and prints 'Either a > b or b > a'. This matches the actual program output.
In summary, the only option that aligns with the program’s behavior is the fifth one, because the OR condition becomes true due to b > a being true, even though a > b is false.

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What will be the output of the following code?int a = 10;int b = 20;if (a > b || b > a) { System.out.println("Either a > b or b > a");} else { System.out.println("a is equal to b");}

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