You prepare a "gel ready sample" with a protein concentration of 1200 µg/mL.

You load 25 µL of this "gel ready sample" in a lane on the gel.

How much protein (in µg) did you load in the gel lane?

Question

You prepare a "gel ready sample" with a protein concentration of 1200 µg/mL.

You load 25 µL of this "gel ready sample" in a lane on the gel.

How much protein (in µg) did you load in the gel lane?

BlackTom AI · Accepted Answer

The problem asks how much protein is loaded into a gel lane when you have a certain concentration and a specific loading volume.
First, convert all quantities to compatible units: 25 µL is 0.025 mL.
Next, multiply the concentration by the volume to obtain the mass loaded: 1200 µg/mL × 0.025 mL = 30 µg.
Now evaluate each option to see if it matches the calculated amount:
- Option 30: Matches the computed value exactly, so this is the correct amount loaded.
- Option 48: This would correspond to 1200 µg/mL × 0.04 mL, or a 40 µL volume, not the 25 µL used here; thus this is incorrect.
- Option 300: This would require 0.25 mL of sample (300 µg = 1200 × 0.25), which is far larger than the 25 µL loaded; thus incorrect.
- Option 21: This would correspond to 1200 × 0.0175 mL, implying a loading volume of 17.5 µL, not 25 µL; thus incorrect.
- Option 3000: This would imply loading 2.5 mL of the sample (3000 µg), which is far beyond the stated 25 µL; thus incorrect.
In summary, only the 30 µg option aligns with the given concentration and loading volume, while all other choices result from using different volumes or misapplying the concentration- volume relationship.

W25 BIOL D006B 01Y Cell & Molecular Biology Lab Quiz 2

You prepare a "gel ready sample" with a protein concentration of 1200 µg/mL. You load 25 µL of this "gel ready sample" in a lane on the gel. How much protein (in µg) did you load in the gel lane?

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