Questions
APBIO141-031 with labs S14 - CollegeBoard* AP Exam Prep: Chi-squared Practice
Single choice
In fruit flies, purple eyes and ebony body are traits that display autosomal recessive patterns of inheritance. In a genetics experiment, students cross wild-type flies with flies that have purple eyes and ebony bodies. The students observe that all the flies in the F1 generation have normal eyes and a normal body color. The students then allow the F1 flies to mate and produce an F2 generation. The students record observations about the flies in the F2 generation and use the data to perform a chi-square goodness-of-fit test for a model of independent assortment. The setup for the students’ chi-square goodness-of-fit test is presented in Table 1. Table 1. The students’ chi-square goodness-of-fit test for a model of independent assortment Phenotype Observed Expected Normal eyes, normal body 187 171 Normal eyes, ebony body 49 57 Purple eyes, normal body 41 57 Purple eyes, ebony body 27 19 The students choose a significance level of p=0.01. Which of the following statements best completes the next step of the chi-square goodness-of-fit test?
Options
A.The calculated chi-square value is 2.11, and the critical value is 11.35.
B.The calculated chi-square value is 10.48, and the critical value is 7.82.
C.The calculated chi-square value is 10.48, and the critical value is 11.35.
D.The calculated chi-square value is 2.11, and the critical value is 7.82.
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Step-by-Step Analysis
The problem asks us to evaluate a chi-square goodness-of-fit test for a dihybrid cross with independent assortment, using the observed and expected counts in Table 1 and a significance level of p = 0.01. Before selecting the correct option, we should compute the chi-square statistic and compare it to the critical value for df = number of phenotypic categories minus 1 (here 4 categories, so df = 3).
Option 1: The calculated chi-square value is 2.11, and the critical value is 11.35.
- Why this is implausible: A chi-square of 2.11 is far smaller ......Login to view full explanationLog in for full answers
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