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Single choice

Cyclobutane, C4H8, decomposes as shown: C4H8(g) → 2 C2H4(g). In the course of a study of this reaction, the rate of consumption of C4H8 at a certain point was 4.50 x 10-4 mol L-1 s-1. What is the rate at which C2H4(g) is being generated at this point, also in mol L-1 s-1?

Options
A.a. 4.50 x 10-4 mol L-1 s-1
B.b. 2.12 x 10-4 mol L-1 s-1
C.c. 2.25 x 10-4 mol L-1 s-1
D.d. 9.00 x 10-4 mol L-1 s-1
E.e. 2.03 x 10-3 mol L-1 s-1
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Step-by-Step Analysis
The reaction is C4H8(g) → 2 C2H4(g). This means that for every 1 mole of C4H8 consumed, 2 moles of C2H4 are produced. Given the rate of consumption of C4H8 is 4.50 × 10^-4 mol L^-1 s^-1, the rate of generation of C2H4 must be twice that value due to the 1:2 stoichiometric ratio. O......Login to view full explanation

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