Which of the following describes the position of Polaris in our local sky here in the bay area?

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BlackTom AI · Accepted Answer

First, recall what Polaris' sky position represents: Polaris is located nearly at the celestial north pole, so its declination is around +90 degrees. For a given observer, the altitude of Polaris above the northern horizon roughly equals the observer's latitude.

Option 1: 90° altitude, 38° declination. This would place Polaris directly overhead (zenith) and have a declination near the observer's latitude, which is inconsistent with Polaris being near the north celestial pole. Therefore this is incorrect.

Option 2: 90° altitude, 0° declination. A 90° altitude implies the object is at the zenith, but a declination of 0° would place it on the celestial equator. Polaris is not on the celestial equator, so this option is wrong.

Option 3: 38° altitude, 90° declination. This matches the expectation for a Bay Area observer at roughly 38° N: altitude of Polaris around the latitude (about 38° above the horizon) and a declination of +90° since Polaris sits near the north celestial pole.

Option 4: 38° altitude, 0° declination. An altitude of 38° is plausible, but a declination of 0° places the object on the celestial equator, not near the north celestial pole. This contradicts Polaris’ true position.

In summary, only the combination of an altitude equal to the observer’s latitude (≈38°) and a declination of about +90° accurately describes Polaris as seen from the Bay Area, while the other options mix incorrect altitude/declaration pairings that do not align with Polaris’ well-known location near the north celestial pole.

ASTR-1-45046-F25 Lecture: Sky Navigation

Which of the following describes the position of Polaris in our local sky here in the bay area?

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