The oxidation of a primary alcohol will produce a compound X.When this compound X reacts with a strong base such as OH-, it will form a

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The question sets up a two-step sequence: first, oxidation of a primary alcohol to form a compound X; second, treatment of X with a strong base like OH-.

Option a: carboxylate ion
- If the primary alcohol is oxidized fully under appropriate conditions, the product is a carboxylic acid (R-COOH). A strong base such as OH− will deprotonate this carboxylic acid, yielding the carboxylate ion (R-COO−). This is a standard acid-base equilibrium: R-COOH + OH− → R-COO− + H2O.

Option b: a hydroxide ion
- Hydroxide is the base in the reaction and is not typically formed by reacting with the carboxylic acid; rather, OH− is consumed as a reactant to deprotonate the acid. The question describes OH− as the base used, not as the product, so this option represents a misinterpretation of the reaction participants.

Option c: a tertiary alcohol
- Oxidation of a primary alcohol does not yield a tertiary alcohol. A tertiary alcohol would require a rearrangement or a completely different precursor, and oxidation of a primary alcohol progresses toward aldehyde and potentially carboxylic acid, not a tertiary alcohol.

Option d: a secondary alcohol
- Similarly, oxidation of a primary alcohol does not produce a secondary alcohol. The carbon skeleton and oxidation state are advanced toward higher oxidation (aldehyde, then carboxylate), not toward converting to a less-oxidized secondary alcohol.

In summary, among the given choices, the pathway that aligns with a primary alcohol oxidation product reacting with OH− to give a deprotonated carboxylate ion is the formation of a carboxylate ion through deprotonation of a carboxylic acid product.

MUF0042 Chemistry Unit 2 - Semester 1, 2025 Post-Lab Quiz: Formative Practical

The oxidation of a primary alcohol will produce a compound X.When this compound X reacts with a strong base such as OH-, it will form a

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