What is the correct syntax to declare a pointer to an array of 10 integers?

Question

BlackTom AI · Accepted Answer

The question asks for the correct syntax to declare a pointer to an array of 10 integers.
Option 1: int (*ptr)[10];
This is the correct form. The parentheses bind the asterisk to the pointer name, indicating that ptr is a pointer to an array of 10 int. The outer structure is a pointer ( *ptr ), and the ( )[10] specifies the pointed-to type as an array of 10 integers.
Option 2: int *ptr[10];
This declares ptr as an array of 10 pointers to int, i.e., an array where each element is an int*.
This is different from a pointer to an array of 10 ints, so it does not meet the requirement of a pointer to an array of 10 integers.
Option 3: int *(ptr[10]);
Despite the parentheses, this also declares an array of 10 pointers to int (same meaning as option 2). The grouping does not create a pointer to an array; it creates an array where each element is a pointer to int.
Option 4: int **ptr[10];
This declares an array of 10 pointers to pointers to int, i.e., each element is an int**. This is even further from the requested type (pointer to an array of 10 ints).
In summary, only option 1 yields a pointer to an array of 10 integers, while options 2, 3, and 4 describe arrays of pointers (or pointer-to-pointer types) rather than a single pointer to an array.

What is the correct syntax to declare a pointer to an array of 10 integers?

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