Q12 V2A compound underwent two tests.In the first test, 1 mole of the compound was completely combusted, yielding 3 moles of CO2.In the second test, the compound did not show any rapid reaction with bromine. The formula of the compound is likely to be:

Question

BlackTom AI · Accepted Answer

To begin, I restate the information given: in the first combustion test, 1 mole of the compound yields 3 moles of CO2 when fully burned. In the second test, the compound does not show any rapid reaction with bromine.

Option a: C3H6. If one mole of this compound were combusted completely, the number of CO2 moles produced equals the number of carbon atoms in the molecule, since each carbon ends up as CO2. C3H6 has 3 carbons, so we would expect 3 moles of CO2, which matches the observed 3 CO2. However, C3H6 is unsaturated (has at least one C=C or C≡C bond). When bromine water is added to an unsaturated hydrocarbon, the bromine adds across the double bond, causing a rapid decolorization. The given second test states there was no rapid reaction with bromine, which argues against an unsaturated hydrocarbon.

Option b: C2H4. This molecule has 2 carbons, so complete combustion would produce about 2 moles of CO2, not 3. Therefore, this option cannot match the first test.

Option c: C4H10. This alkane has 4 carbons, so complete combustion would yield 4 moles of CO2 per mole of fuel, again not matching the observed 3 CO2. So this option is inconsistent with the first test.

Option d: C3H8. This is a saturated hydrocarbon (propane) with 3 carbons. Upon complete combustion, it would indeed yield 3 moles of CO2 per mole of fuel, aligning with the first test.

Now, considering the second test: the compound did not show any rapid reaction with bromine. Saturated hydrocarbons like alkanes (e.g., C3H8) do not react readily with bromine under normal conditions, whereas unsaturated hydrocarbons (like C3H6) react rapidly due to the presence of carbon–carbon multiple bonds. Therefore, the lack of a rapid bromine reaction further supports a saturated formula.

In summary, the requirement from the first test intersects with the requirement from the second test: a 3-carbon, saturated hydrocarbon matches both observations. The combination of these two pieces of evidence narrows the possibilities to a propane-type molecule that is fully saturated, which is consistent with C3H8.

MUF0042 Chemistry Unit 2 - Semester 2, 2025

Q12 V2A compound underwent two tests.In the first test, 1 mole of the compound was completely combusted, yielding 3 moles of CO2.In the second test, the compound did not show any rapid reaction with bromine. The formula of the compound is likely to be:

View Explanation

Log in for full answers

Similar Questions

Which of the following substances would decolourise bromine? .

In a consumer society, many adults channel creativity into buying things

Economic stress and unpredictable times have resulted in a booming industry for self-help products

People born without creativity never can develop it

A product has a selling price of $20, a contribution margin ratio of 40% and fixed cost of $120,000. To make a profit of $30,000. The number of units that must be sold is: Type the number without $ and a comma. Eg: 20000

Which of the following statement regarding cost is correct:

Under the assumptions used in cost-volume-profit analysis, as the activity increases:

The CVP and break-even analysis are supported by a range of important assumptions. Which of the following is not an assumption of the CVP:

More Practical Tools for Students Powered by AI Study Helper

Homework AI Solver

Stylized AI Paper Writer

Plagiarism Checker Assistant

Citation AI Academic Writing Tool

In-Class Translation Assistant

AI Note Generator

AI Quiz Answers

Past Exam Questions from University Test Bank

Smart Practice Assistant

Adaptive Practice

Making Your Study Simpler