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1A W25 VidQuiz: MO Theory: Mixing P-orbitals

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Using the electron configurations you found in question 2, determine the bond order for each of the following diatomic molecules.  1: H_2 2: He_2 3: Li_2 4: Be_2 5: B_2 6: C_2 7: N_2 8: O_2 9: F_2 10: Ne_2

Options
A.0
B.1
C.2
D.3
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Step-by-Step Analysis
We are asked to determine bond orders for a set of diatomic molecules using electron configurations from question 2, and then match those bond orders to the provided answer options. The answer options are the strings: "0", "1", "2", and "3". The given answer array is ["1", "0", "2", "3"], which seems to map the first four molecules to those option values. To evaluate this properly, I’ll first establish the standard bond orders for the diatomic molecules typically analyzed with MO theory based on valence electrons. Option 0: Bond order = 0 - In MO terms, a bond order of 0 would mean no net bonding interaction between the two atoms (n_b = n_a). This would imply that the molecule has no stable bond in the simple MO picture. In practice, very few stable diatomic molecules have bond order 0 under simple MO counting; Be2 has historically been described as having bond order 0 because its 4 valence electrons fill the σ2s (bonding) and σ2s* (antibonding) orbitals equally (n_b = 2, n_a = 2). If we apply this to H2 through Ne2, a bond order of 0 would incorrectl......Login to view full explanation

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