What is the boiling point of a solution of 0.1 mole of glucose in 200 mL of water? (K = 0.512C/m)

Question

BlackTom AI · Accepted Answer

To approach boiling-point elevation, I start by identifying the key relation: ΔTb = i · Kb · m. Here, the solute is glucose, which does not ionize in solution, so i = 1. Next, I need the molality m, which is moles of solute per kilogram of solvent. We have 0.1 moles of glucose in 200 mL of water. Assuming the density of water is close to 1 g/mL, 200 mL corresponds to about 200 g, i.e., 0.200 kg of solvent. Therefore, m = 0.1 mol / 0.200 kg = 0.5 m.

Now compute the boiling-point elevation: ΔTb = (1) · (0.512 °C·m) · (0.5 m) = 0.256 °C. The normal boiling point of water is 100.0 °C, so the new boiling point is 100.0 °C + 0.256 °C ≈ 100.256 °C. Depending on rounding, this is commonly reported as 100.26 °C.

Evaluating the answer choices:
- 100.06 °C: This would correspond to a ΔTb of about 0.06 °C, which is far smaller than the calculated 0.256 °C, implying a much smaller molality or an incorrect Kb value. This does not fit the given data.
- 100.13 °C: This implies a ΔTb around 0.13 °C, still significantly less than the expected 0.256 °C; the molality or Kb used would have to be roughly half of the actual calculated values, which is inconsistent with the provided Kb and solute amount.
- 100.26 °C: This matches the computed Boiling point, given the calculated ΔTb of about 0.256 °C and the standard water bp of 100.0 °C. This is the correct scale for the precision used here.
- 100.5 °C: A ΔTb of 0.5 °C would require either a larger molality or a larger Kb than given; with m = 0.5 m and Kb = 0.512 °C/m, the elevation is about 0.256 °C, not 0.5 °C, so this option is inconsistent with the data.

In summary, by applying the colligative property formula and plugging in the provided values, the computed boiling point shift aligns with the 100.26 °C option, while the other values do not correspond to the calculated ΔTb using i = 1, Kb = 0.512 °C/m, and m = 0.5.

Chemistry (H) - Varnold - Preparatory Academy - 2nd Semester - 2024/2025 2025 States of Matter and Solutions Practice Test

What is the boiling point of a solution of 0.1 mole of glucose in 200 mL of water? (K = 0.512C/m)

View Explanation

Log in for full answers

Similar Questions

What is the boiling point of a solution of 0.1 mole of glucose in 200 mL of water? (K = 0.512C/m)

What is the boiling point of a solution that contains 3 moles of KBr in 2000 g of water? (K = 0.512C/m; molar mass of water = 18 g)

What is the boiling point of a solution that contains 3 moles of KBr in 2000 g of water? (K = 0.512C/m; molar mass of water = 18 g)

Ignoring ion pairing, which aqueous solution has the highest normal boiling point?

In a consumer society, many adults channel creativity into buying things

Economic stress and unpredictable times have resulted in a booming industry for self-help products

People born without creativity never can develop it

A product has a selling price of $20, a contribution margin ratio of 40% and fixed cost of $120,000. To make a profit of $30,000. The number of units that must be sold is: Type the number without $ and a comma. Eg: 20000

More Practical Tools for Students Powered by AI Study Helper

Homework AI Solver

Stylized AI Paper Writer

Plagiarism Checker Assistant

Citation AI Academic Writing Tool

In-Class Translation Assistant

AI Note Generator

AI Quiz Answers

Past Exam Questions from University Test Bank

Smart Practice Assistant

Adaptive Practice

Making Your Study Simpler