A black body glowing in blue color is at a higher temperature than another black body glowing in yellow color.

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When evaluating a black body’s color in relation to temperature, we rely on blackbody radiation principles. As temperature rises, the peak of the emitted spectrum shifts to shorter wavelengths, moving from red through orange and yellow toward white and eventually bluish hues. Therefore, a body that glows blue is emitting light with a peak at shorter wavelengths than a body that glows yellow, which corresponds to a lower peak-wavelength and thus a lower temperature than the blue source. In other words, for ideal black bodies, higher temperature produces colors closer to blue, while lower temperatures yield redder colors such as red or yellowish tones. While factors like lamp intensity, atmosphere, or observer perception can subtly affect perceived color, the underlying relationship described by Planck’s law and Wien’s displacement law indicates that blue emission implies a higher temperature than yellow emission. Consequently, there is a consistent physical basis for comparing the two colors in this way and the statement aligns with that understanding. Note that in real-world situations, calibration and context matter, but the core concept remains: color shifts to blue with increasing temperature, so the blue-glowing body is hotter than the yellow-glowing one.

CHEM1012 (L2) Online Quiz #1

A black body glowing in blue color is at a higher temperature than another black body glowing in yellow color.

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