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BST6, BST_Srch11 Based on our Binary Search Tree search method discussions in our lectures. Below is an algorithm written for BST search. This is not an AVL Tree so balancing is not a concern. What would be the run time complexity on average of this search algorithm written for a BST ? BSTSearch(tree, key) { cur = tree⇢root while (cur is not null) { if (key == cur⇢key) { return cur // Found } else if (key < cur⇢key) { cur = cur⇢left } else { cur = cur⇢right } } return null // Not found }
Options
A.O(n2)
B.O(logn)
C.O(nlogn)
D.O(n)
E.O(1)
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Question: Determine the average-case run time complexity of BSTSearch for a standard binary search tree (not AVL) when searching for a given key.
Option 1: O(n^2) – This would imply the algorithm visits many nodes in a way that multiplies with n, which is not how a single BST search behaves. Each iteration moves down one level of the tree, not performing quadratic work. Therefore, O(n^2) is not a correct characterization of the ty......Login to view full explanationLog in for full answers
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BST_Srch3 Below is a BST When searching for Node 78 which node is visited 4th? Note that this is a BST not an AVL tree. AVL balancing is not a concern.
CC7_03 Create a function that takes in a Binary Search Tree (BST) and a positive integer k, returning the kth largest integer value within the BST. Assume that the BST only contains integer values and that k will always be less than or equal to the total number of nodes in the tree. For this question, duplicate integers are treated as distinct entries. For instance, in a BST with values {5, 7, 7}, the second largest value would be 7—not 5. Each BST node has an integer value, a left child node, and a right child node. A node is a valid BST node only if it adheres to the BST properties: its value is strictly greater than all values of nodes in its left subtree, and less than or equal to all values of nodes in its right subtree. The children nodes are either valid BST nodes themselves or None / null. Sample input: Sample output: 17 Given the following implementation to traverse_reverse_in_order(node, k, tree_data), which test case would fail? It is guaranteed that all the other methods are correctly implemented. The input trees depicted in the DcStrings of test cases are guaranteed to be accurate.
CC7_01 Create a function that takes in a Binary Search Tree (BST) and a positive integer k, returning the kth largest integer value within the BST. Assume that the BST only contains integer values and that k will always be less than or equal to the total number of nodes in the tree. For this question, duplicate integers are treated as distinct entries. For instance, in a BST with values {5, 7, 7}, the second largest value would be 7—not 5. Each BST node has an integer value, a left child node, and a right child node. A node is a valid BST node only if it adheres to the BST properties: its value is strictly greater than all values of nodes in its left subtree, and less than or equal to all values of nodes in its right subtree. The children nodes are either valid BST nodes themselves or None / null. Sample input: Sample output: 17 Given the following implementation to traverse_reverse_in_order(node, k, tree_data), which test case would fail? It is guaranteed that all the other methods are correctly implemented. The input trees depicted in the DcStrings of test cases are guaranteed to be accurate.
BST_I_18 Examine the Binary Search Tree (BST) depicted below: You are inserting a new node with the value 250 into the BST shown below. Currently, you are examining the node with the value 200. According to the standard BST insertion algorithm (no AVL balancing), what is the next step?
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