When a belt drive is transmitting maximum power

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To evaluate the statements, I’ll consider how belt drives behave when transmitting maximum power and how tensions relate to centrifugal effects.
Option 1: 'Effective tension is equal to the centrifugal tension.' This would imply T1 - Tc or T2 - Tc equals Tc, which is not a standard condition for maximum power. In practice, the effective tension (the difference between tight and slack tensions minus centrifugal effects) is not simply equal to Tc. This makes the claim misleading.
Option 2: 'Effective tension is half of the centrifugal tension.' Again, there is no conventional belt-design criterion that sets the effective tension to Tc/2. The effective tension is tied to the net driving force (T1 - T2, adjusted for Tc), not a fixed simple half of Tc. Therefore this is incorrect.
Option 3: 'Driving tension in slack side is equal to the centrifugal tension.' This aligns with the known condition for maximum power transmission in belt drives: under maximum power, the driving (tight) and slack tensions, when reduced by centrifugal tension, reach a balance that makes the slack-side driving tension equal to Tc. In other words, T2 ≈ Tc in the limiting case, indicating that the driving tension on the slack side matches the centrifugal tension. This is a recognized criterion in belt-passage analysis for maximum power.
Option 4: 'Driving tension in tight side is twice the centrifugal tension.' This overstates the relationship; while centrifugal tension Tc contributes to the net tensions, the standard maximum-power condition does not state that the tight-side driving tension is exactly 2Tc. It depends on belt geometry, speed, and load, and cannot be asserted as a universal rule. Hence it’s not correct.

OENG1068 Quiz 1 - Mechanical Design

When a belt drive is transmitting maximum power

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