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Question at position 8  If y' = 6x - 3 and y(2) = 4, then y =6x2 - 3x + 2.3x2 - 3x + 2.3x2 - 3x.3x2 - 3x - 2.6.

Options
A.6x2 - 3x + 2.
B.3x2 - 3x + 2.
C.3x2 - 3x.
D.3x2 - 3x - 2.
E.6.
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Step-by-Step Analysis
Let me restate the problem to anchor our work: We are given y' = 6x - 3 and the initial condition y(2) = 4. We need to find the function y in terms of x and then compare against the provided answer choices. Option 1: 6x^2 - 3x + 2. This would come from integrating y' to obtain y = 3x^2 - 3x plus a constant, not 6x^2. The coefficient of x^2 here is 6 instead of 3, so this option is inconsistent with the derivative given. Moreover, evaluating at x = 2 would yi......Login to view full explanation

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