In the reaction, HClO3 + N2H4 ⇌ ClO3– + N2H5+, which one of the sets below lists both of the acid species involved in the equilibrium?

Question

In the reaction, HClO3 + N2H4 ⇌ ClO3– + N2H5+, which one of the sets below lists both of the acid species involved in the equilibrium?

BlackTom AI · Accepted Answer

To identify the acid species in the given equilibrium, let's first recall the reaction: HClO3 + N2H4 ⇌ ClO3– + N2H5+. In this context, acids are species that donate protons (H+).
Option a: HClO3, N2H4. Here HClO3 is indeed an acid in aqueous solution (it donates H+ to become ClO3–), but N2H4 (hydrazine) is a base, not an acid, so this pair does not list both acid species.
Option b: HClO3, N2H5+. HClO3 is an acid, and N2H5+ (hydrazinium) is also an acidic species (it can donate a proton to revert to N2H4). This pair correctly identifies the two acid species participating in the equilibrium as written, making this option accurate.
Option c: N2H4, N2H5+. N2H4 is a base rather than an acid, while N2H5+ is an acid; since the pair includes a base rather than an acid, this option is incorrect for listing both acid species.
Option d: N2H4, ClO3–. N2H4 is a base, and ClO3– is the conjugate base of HClO3, not an acid; therefore this combination fails to list the acid species involved in the equilibrium.
In summary, only option b correctly lists both acid participants in the reaction HClO3 + N2H4 ⇌ ClO3– + N2H5+, since both HClO3 and N2H5+ are acids in this context, while the others mix acids with bases or conjugate bases, leading to incorrect pairings.

In the reaction, HClO3 + N2H4 ⇌ ClO3– + N2H5+, which one of the sets below lists both of the acid species involved in the equilibrium?

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